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Algebra is boring.
No! Algebra is Magic!
Magic?
Yeah, Magic. You know that Magic isn’t really “magical”, right? I mean, it’s not supernatural. There’s always some clever hidden mechanism that makes it work. The illusion is cool, but to me the best part is trying to figure out how they did it! It’s like what makes mystery books and movies so interesting, trying to figure out who murdered the butler, and how.
Okay, Mister Magic, so why is algebra magic?
Okay, here’s a cool magic trick for you: You know how numbers have two square roots, right?
Sure, like the square root of is
and
, because multiplying two negatives makes a positive.
Right! Well, it turns out that there are the same number of roots for any number as the root term. That is, two square roots, three cube roots, four fourth roots, … fifty two fifty-second roots, and so on.
Okay…? That’s a little weird.
So how do you find them? Like how do you find the three cube roots of ?
Well, one of them is , right?
Yeah, and the other two?
No idea.
Okay, so here’s the trick: The positive root, say, , which is one of the three cube-roots of
, is easy to find. You knew that one, and if it wasn’t something you knew, or could easily figure out, you could just use a calculator to find it.
Okay, but you’re telling me that there are two more cube roots of . Is one of them
?
Nope. is
.
Oh, right. Multiplying by the negative keeps flipping it. So an odd power of a negative number will be negative.
Right. There are two more, but they’re complex.
Complex like complicated, or complex like the square root of , that’s
, right?
The kind of complex.
I kinda figured.
So, you know that every number has a complex representation, right? jIt’s just that when we do simple math, the part — the ‘imaginary’ part — is usually zero, so we just leave it off.
Right, so is the same as
, and
is the same as
.
Exactly! And you remember how to plot complex numbers on the complex plane? The first part — the ‘real’ part — is on the axis, and the imaginary part — the ‘i’ part — is on the
axis.

Right. Okay. I’m with you so far.
Great. We need just one more thing, which you already know in a slightly different context: You multiply complex numbers just like you multiply polynomials, by summing all the cross-products. So, like: is
. So far so good?
I prefer FOIL — First, Outside, Inside, Last.
Okay, that’s fine. It’s the same thing, just in a different order.
Okay, great. But I don’t see how this review of last year’s algebra is going to magically get me the other two cube roots of .
We’re about to get to that right now. But first, let’s prove that the complex versions of square roots work. This will also give us a little simple practice in multiplying complex numbers by FOIL.
Okay.
Let’s FOIL out plus zero
times
plus zero
, that is
By FOIL that’s
All the zeros just zero out, so you’re left with which, conveniently, is 4 !!
Okay, let me try the other side: is
And again, we’re left with , which is, not coincidentally, also
!!
Okay, but that’s just cheating. All the imaginary parts just zeroed one another out. So what?
Ah, but that’s just for square roots. Let’s try fourth roots.
Fourth roots? Why not cube roots next?
Fourth roots turn out to be a bit easier for a reason that you’ll understand soon.
Okay, fine. Fourth roots, then.
So, what are the fourth roots of , that is
?
?
Don’t forget the negative root.
Oh, okay, and
, right?
Right, because multiplying an even number of negative numbers results in a positive number.
But you’re going to tell me that there are two more complex ones, right?
Right. But first, it’s important to keep in mind that these all really complex. is really
, and
is really
.
Okay, fine. This isn’t very magical.
Not yet, but we’re building the clever machine that makes the magic happen.
Let’s plot these on our complex plane.
Here’s and
.

Now, here’s the magical core of the machine: It turns out that all the roots of a number are evenly spaced around the circle whose radius is the positive root of the number. So, the four fourth roots of are here:

See that’s , which is
units up the
axis — that is, the
axis. And
is
units down the
axis. Those are the other two roots of
!!
Really?
Yup. Let’s prove it by raising to the fourth power, that is:
We could do either one, but
is the less obvious one.
Okay. You’ll have to follow me through it so I don’t make a mistake. That’s a lot of FOILs!
We can simplify even roots a bit. You agree that raising to the fourth power is the same as sqauring it, and then squaring the result, right?
Sure. It’s Like . Right?
Exactly! So go ahead and do the first FOIL of .
Okay, so that’s . The first three terms just get zero’ed out, right?
Right, so what’s left?
The last term , which is
squared, that is:
.
Good, and what does that work out to? Be careful how you distrbibute the square!
Um, let’s see, that’s squared times
squared, or
.
is just
, and
is the fundamental complex result:
. So the result is
. Wait! What happened to the
?!
Abracadabra! You just saw some of the magic machinery at work. The vanished in a poof of squaring, and as it vanished it turned into a
, and flipped the
to a
.
Oh. Cool.
But we’re not done, that’s only half the problem.
Oh yeah, we were doing four of them.
Right, but we agreed that you could multiply one pair of them, which you just did, and then multiply those results together again, like we agreed above with all the s.
Hold on, I sort of lost my place. … Yes, that’s right, it was , which is
, and then that squared again.
And we just figured out that squared is what?
So that squared again is … ?
…which is what we were looking for! Cool!
You want to try showing that ?
I’ll take your word that it will do the same thing. Now that I’ve seen the magical action, I can sort of see how that will work out.
Good! So we found the four complex roots of :
,
,
, and
, or, more precisely:
,
,
, and
.
You can see how they are neatly spaced around the circle with radius right? Here it is again, because this picture is really important!

Right. Cool. I think I can see where we’re going next.
Okay, you tell me, then.
So to get the cube root of something, you divide the circle into three parts instead of four, right?
Exactly! So to make things simple, let’s use again, whose “real” root is
, as our starting point.
So, addition to , we think that there must be two more cube roots of
. We know that
isn’t one of them…because the negative would flip it three times. (
is a cube root of
, but not of
.)
Okay. Maybe. I’m not gonna think about the , and just stick to the cube roots of
for now.
Good idea. So using the complex plane geometry trick, where should the other roots be?
Um, let’s see. So, one of them is , that is,
. Let’s plot that on the complex plane.

Good.
And since there are two more, and they have to be evenly spaced around the circle, they must be at and
degress, here and here. So are they
and
?
Well, no. If you look at the picture more carefully, the radius of the circle is , but those points aren’t
on the
and
axes. Can you figure out what they are? I’ll give you a hint: Notice that the upper root is a bit to the left of the
axis. How many degrees is that gap?
is
.
Right, So, let me draw a right triangle for you.

The hypotenuse is the radius. We’ve agreed that that’s . And we know that the gap angle is
, so the remaining angle is
. You should be able to take it from here.
Oh! It’s a triangle!
Exactly!
I can never remember how they go.
Neither can I, actually. I’ll look it up.
[Brief pause while web searching takes place!]
If the hypotenues is , the short leg is
and the long leg is
-root-$3$ (
), that is,
times the square root of
.
Ugh. This is going to be a mess!
Not really. Conveniently the hypotenuse is , so
is just
. So the short leg is
and the long leg is just the
. So what’s that point in complex space?
Um. ?
Other way ’round!
Oh, sorry. .
Almost; Watch your signs. Use the diagram as a guide. The is negative and the
is positive
Oh, so .

Right! So now can you prove to yourself that that’s a cube root of ?
Seriously?! How could something with a square root of in it be a cube root of
?!
Indeed! Let’s crank up the magic machine and see.
Okay so…
Let’s do two of them first: .
FOILing gets us , which is
This seems to be getting worse, not better!
Keep cranking!
Okay so squaring () is
which is just
, and
is
, so that’s
all together, so we have
, or
Ugh. Now what?
Well, you could just push through the next FOIL multiplcation by , but I suggest factoring out a
, and setting it aside for later.
Okay, so that times
… almost like the remaning term.
Great, so FOIL those two.
Okay is
.
Right! And…?
The middle terms cancel out!
Right! Go on….
So we have
squared is, again,
, or
so that’s
… Hey, where’d all the roots go?!
Magic! Go ahead and finish it.
Okay, so that’s , which is
!
Exactly!
But we were supposed to get !
Think about it….
Oh! Oh! The we factored-out and set aside!
Exactly, so…?
So that’s times the factored-out
, which is …
!
Holy cow!
Yeah, Magic, Eh?
One way to think about what’s happening, is that the complex plane is a machine — the machine behind the magic trick — that lets you use geometry to reason about numbers. When you mlutply numbers on the complex plane, you’re multiplying the length of the radius (the hypotenuse of that right triangle), and rotating around the circle. Squaring a complex number squares the real part, and also rotates around the circle by exactly the angle from (the
axis).
I see. Cool!
So, then you should be able to think out the answer to this question…
Um, okay…?
You know that is the square root of
, that is:
, right?
Yeah.
So, show that on the complex plane picture.
Oh, well, okay, so the radius is has to be the square root of , right?
Right.
So that’s just , but when I do the square I want it to end up on the left
axis, which is
, or
Right, so where does it have to be?
Um here?

Exactly! And what’s that point in complex terms?
Oh. I see: .
Right. And since we don’t bother writing out zero parts, nor ones, it’s just …?
!!!
Exactly! Now, remember that there are exactly two square roots of any number.
I’m ahead of you! It’s down at … But wait a minute! When I square that, won’t it rotate up to
?
Ah, excellent question! That’s the first thing that comes to mind, but , or
, is actually
degrees from
, so when you square it, it will rotate another
degrees…
I see … Right to where we expect it to be: , or just
!!
Perfect! Okay, seems like you get how the machine behind the magic works. So here’s one that will blow your mind: What are the square roots of ?
Um… Does even have a square root?
Every number has two square roots, including ! Just treat it exactly like you did the square root of
. First, where’s
?
Oh, well, I’m already there. That was just the answer to the last problem: , up here.

Right, and where would you have to be for the squaring and rotation rule to work?
Um, so square root of is just
, so the length of the radius will just be one…and it’ll be half way between
and
, that is
, right?

Right, so where’s that point?
Oh heck, it’s someplace in weird root space again … at degrees!
Yeah, but this one’s easy to figure out because the it’s just an isosceles right triangle. Or, even easier, the sides of a square with diagonal . So what’s that point?

in each direction?
?
Close. That would be if the sides of the square were and we wanted the diagonal. This is the other way around: The diagonal is
. Running the pythagorean theorem backwards you’ll see that it’s actually the square root of
, or
. So what’s that point?
Um,
Yup! (By the way, you’ll often see written as
or as
. Someday it’s worth proving to yourself that these are all the same thing, but for the moment let’s just leave it as
.)
Ugh. Roots! Is this really going to work?!
Roots are great, especially when you multiply them by themsevles because you get the number back! Also, it turns out that plays a central role in physics, especially quantum mechanics!
Can we just stick to this problem. Quantum mechanics will make my brain hurt.
Fine. Anyway, go ahead and work it out.
Okay, so FOILs to
This is never gonna work!
Don’t bet on it. Just push it through and trust the magic!
Okay, so that’s, um, squared, which is
Good! Now do the last term first, because we’re used to those.
(One of the magical things here is that the last term in the FOIL combines with the first term, so it’s convenient to do them together, and worry about the middle terms later. If you watch closely, what’s happening is that the end terms and the middle terms keep switching places, ping-ponging the back and forth between them!)
Okay, so is
, which is, um,
, Oh! So that cancels the first term!
Right, so the real part is just zero. Now do the middle ones.
…hmmmm… well, that’s just
times
. That’s a little complex. Ha ha!
Yeah. Ha ha. I suggest breaking that product into parts to make it more obvious.
Okay, so that’s . The
is just
, which is just
, and
is just
. and that times
is just …
Holy cow again, it’s just !!
So the whole complex result is…?
?
Right, which, again is just…?
!!
See, Magic!
Okay. Yeah… Magic! Truly So!
Now remember that every number, including , has two square roots! Given what you already know, you can figure out, just by eye, where the other one is.
And, given all this, you can probably now figure out both square roots, all three cube roots, and all three hundred and fifteen three-hundred and fifteenth roots of any number! (A little trig, and a calculator will help a lot for figuring out the complex coordinates of weird angles, like !!)
On it!










!!! From there it’s easy: Set a=1 to get it out of the way, then half way between -4 and +2 is … actually, we got this wrong at first … forgot zero! … it’s -1 (best to use the mean: (-4+2)=-2/2=-1), and then plug x=-1 into the equation, and, voila: -9. The “a” is just a scaling factor, so the answer is A: -9a.




